Force diagram

vendredi 28 février 2014

The vertical motion of an elevator is recorded and a Position vs Time plot is generated. The plot is shown in the image attached.





1. Construct a scale drawing of the associated Velocity vs Time plot complete with axis labels.



2. Calculate the average acceleration for the time interval t =8.0s to t = 10s.



3. Sketch a force diagram of an elevator occupant with a mass of 70 kg during the time interval t =8.0s to t = 10s.



4. Calculate the Normal force F N of the occupant using the acceleration you calculated in part 2



Can somebody please tell me where I went wrong? Thanks!!



Mt attempt:

1. Velocity during 0 to 10 = 14 m / 10 s = 1.4 m/s

Velocity during 10 to 19 = 0 m/s

Velocity during 19 to 25 = -14 m /6 s = - 2.33 m/s



2. a = delta v/delta t = 0 - 1.4 m/s/2 s = -0.7 m/s^2



3. I have no clue. How do you figure this one out?



4. Fn = 70 kg * -2.33 m/s^2 = -163.10 N




Attached Images





File Type: jpg p vs t graph.JPG (27.1 KB)







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