Vapor composition from bubble-point temp.

jeudi 31 octobre 2013

Suppose you have a mixture of 30 mol% pentane and 70 mol% hexane at 1 atm and 60oC.



If the Tbubble-point = 55.1oC, calculate the composition of vapor of the first bubble as the mixture is heated.



I found p*pentane = 1392.95 and p*hexane = 484.96 using Antoine's equation with T = 55.1.



Now I suppose I must use Raoult's law as:



yaP = xap*a(@55.1oC)



Using this I get xpentane = (0.7*760)/1392.96 = 0.382



However, the answer sheet says xpentane = 0.55.



Can anyone figure where I'm mistaken?






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