http://i.imgur.com/KXYnkqL.png
I drew up the picture in cad so that you can look at it. The find torque would i take the cross product of the length of the beam (10m) and the component of the force that is applied perpendicular to the beam (50Nsin45°)? I then get ≈353.55Nm and then use the right hand rule to find that the direction is out of the page (or screen).
Is that all correct, cause another student said that I am supposed to multiply the horizontal component of the beam by the portion of the force perpendicular to the beam (10mcos45° * 50Nsin45) to find the magnitude of the torque. This seems backward to me cause that seems like a dot product and I thought that torque was defined as the cross product of the position vector and the force vector.
I drew up the picture in cad so that you can look at it. The find torque would i take the cross product of the length of the beam (10m) and the component of the force that is applied perpendicular to the beam (50Nsin45°)? I then get ≈353.55Nm and then use the right hand rule to find that the direction is out of the page (or screen).
Is that all correct, cause another student said that I am supposed to multiply the horizontal component of the beam by the portion of the force perpendicular to the beam (10mcos45° * 50Nsin45) to find the magnitude of the torque. This seems backward to me cause that seems like a dot product and I thought that torque was defined as the cross product of the position vector and the force vector.
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