schrodinger's cat again

samedi 28 juin 2014

I'm not going to pretend i know everything about quantum theory nor even part of it. All I have is a incomplete basis of how things work. Please try to bare with me as I describe my gedankenexperiment.



Suppose we have the usual set up of schrodinger's cat, A cat in a box that might be either dead or alive based on a decaying atom that we cant know the state of until we look in the box. Suppose before we actually set this experiment up, we entangled radioactive particle with a non-radioactive particle. Then we separated the two of them, putting one in the box, and moving the other to another location to be measured at a later time. Assuming the the cat doesn't some how measure the radio active atom so entanglement is still viable. What happens if we wait long enough for the atom to be equally in the state of decayed and not decayed. And then measure the outside atom? Would we cause the atom inside to pick a state, and would that state be the same as if we were to open the box and look? Also how does the entanglement deal with the fact that there are 3 outcomes and it can only choose 2? ( either the atom is not decayed (so the outside atom can be up or down) or the atom is decayed and ='s neither up nor down??? or does it still have to pick?) Not sure what state the atom would be in, or how we could tell weather the atom had decayed.



the point of this is to see if we can know whether or not the atom is in two states at once ( the cat is both alive and dead) or it is just probability that the cat is either alive or dead.





Thank you everyone who reads this. Please feel free to add anything to my description if it is lacking or flawed.





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