We have
[A,B] equals zero, commuting
[A,B] not equals zero, not commuting
[A,B] = - [B,A] , anti-commuting
So then we can say
[X,P] anticommutes, since [X,P]= -[P,X] , and
[X,P] does not commute, since [X,P] = ih
I find that confusing. Is there something I missed? (Is this on the one hand math language for the Lie algebra, which needs to be anti-commuting, and on the other hand physics language for commuting and non-commuting observables?)
Also, for femions there is the anti-commuting relations {A,B}. Here A,B anticommute if {A,B} is zero. But X and P for bosons anticommute, why are we here not using the anticommutator.
Can someone unconfuse me?
thanks
[A,B] equals zero, commuting
[A,B] not equals zero, not commuting
[A,B] = - [B,A] , anti-commuting
So then we can say
[X,P] anticommutes, since [X,P]= -[P,X] , and
[X,P] does not commute, since [X,P] = ih
I find that confusing. Is there something I missed? (Is this on the one hand math language for the Lie algebra, which needs to be anti-commuting, and on the other hand physics language for commuting and non-commuting observables?)
Also, for femions there is the anti-commuting relations {A,B}. Here A,B anticommute if {A,B} is zero. But X and P for bosons anticommute, why are we here not using the anticommutator.
Can someone unconfuse me?
thanks
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