1. The problem statement, all variables and given/known data
Calculate the arclength of the curve given parametrically by
x=2t^2
y=(8/5)sqrt(3)t^(5/2)
z=2t^3
for 0≤t≤2
2. Relevant equations
S=∫sqrt(x'^2 + y'^2 + z'^2)
3. The attempt at a solution
1. Found derivative of each and input into equation.
2. S=∫sqrt(16t^2 + 48t^3 + 36t^4)dt
3. S=∫2t sqrt(4 + 12t + 9t^2)dt
4. Used complete the square
=∫2t (t+ (3/2))dt
5. Integrated.
[(2/3)t^3 + (3/2)^t^2]
Which evaluated becomes 34/3. The right answer is 24. Where did I go wrong?
Calculate the arclength of the curve given parametrically by
x=2t^2
y=(8/5)sqrt(3)t^(5/2)
z=2t^3
for 0≤t≤2
2. Relevant equations
S=∫sqrt(x'^2 + y'^2 + z'^2)
3. The attempt at a solution
1. Found derivative of each and input into equation.
2. S=∫sqrt(16t^2 + 48t^3 + 36t^4)dt
3. S=∫2t sqrt(4 + 12t + 9t^2)dt
4. Used complete the square
=∫2t (t+ (3/2))dt
5. Integrated.
[(2/3)t^3 + (3/2)^t^2]
Which evaluated becomes 34/3. The right answer is 24. Where did I go wrong?
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