Koch Snowflake Proof by Induction.

dimanche 13 juillet 2014

Hi, I was wondering if there is a way to prove the area of the Koch Snowflake via induction?

At the moment I have the equations:

An+1=An+[itex]\frac{3√3}{16}[/itex]([itex]\frac{4}{9}[/itex])n

and

An=[itex]\frac{2√3}{5}[/itex]-[itex]\frac{3√3}{20}[/itex]([itex]\frac{4}{9}[/itex])n

These two don't seem to work together very well when trying to prove by induction. Can anyone offer any advice? This is not homework by the way :).





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