Molar Heat of Neutralization

1. The problem statement, all variables and given/known data



Calculate the molar neutralization heat of nitric acid (HNO3) using the following data:



Before Neutralization:



HNO3 (0.5 mol/L)

V = 200 ml

T= 23 Celsius



LiOH (1 mol/L)

V = 200 mL

T = 25 Celsius



After Neutralization:



V = 400 mL

T = 27.5 Celsius



2. The attempt at a solution



Calculating the total heat released by Nitric Acid:



q=mcDT

= (400)(4.184)(27.5-23)

= 7531.2 Joules



Calculating moles of Nitric Acid:



C= n/v

(0.5 mol/L) x (0.2) = 0.1 moles Nitric Acid



Calculating Molar Heat of Neutralization:



= (-7532.2 Joules / 1000) / (0.1 moles)



= -75 KJ / mol



Can someone please verify if this is done correctly? Thank you.