solve exponential equation

samedi 2 novembre 2013

1. The problem statement, all variables and given/known data



200n = 2^(n-1) find n





3. The attempt at a solution



200n = 2^(n-1)

200 = 2^(n-1)/n

ln(200) = ln(2^(n-1)/n)

ln(200) = ln(2^(n-1)) - ln(n)

ln(200) = (n-1) * ln(2) - ln(n)

5.3 = .7n - .7 - ln(n)

6 = .7n -ln(n)



This is where I get stuck, not sure if this is the right approach.











1. The problem statement, all variables and given/known data



6n^2 = 2^(n-1) find n





3. The attempt at a solution



6n^2 = 2^(n-1)

ln(6n^2) = ln(2^(n-1))

2 * ln(6n) = (n-1) * ln(2)

2 * ln(6n) = .7n -.7





Stuck again






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