Linear and Rotational Kinetic Energy

mardi 29 octobre 2013

1. The problem statement, all variables and given/known data



A solid cylinder is rolling without slipping. What fraction of its kinetic energy is linear?



2. Relevant equations



Ke=[itex]\frac{mv^2}{2}[/itex]+[itex]\frac{I(v/r)^2}{2}[/itex]



3. The attempt at a solution





Ke=[itex]\frac{mv^2}{2}[/itex]+[itex]\frac{(v/r)^2}{2}[/itex]*[itex]\frac{(mr)^2}{2}[/itex]



Ke=[itex]\frac{3(mv)^2}{4}[/itex]



Linear Ke =[itex]\frac{(mv)^2}{4}[/itex]



Fraction of Linear Ke = [itex]\frac{linear Ke}{Ke}[/itex] = [itex]\frac{(1/4)}{(3/4)}[/itex] = [itex]\frac{1}{3}[/itex]






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