1. The problem statement, all variables and given/known data
The z component of the magnetic dipole moment due to the spin of an electron about its axis is μz = +/- eh/4∏m, where h = 6.63 x 10-34 J s is Planck's constant. A) If μz is parallel to a magnetic field of 10 T, how much energy in electron volts must be supplied to reverse its direction so that it is opposite to the field?
B) Find the ratio of this energy to the 13.6 eV needed to remove an electron from a normal hydrogen atom.
2. Relevant equations
μz = +/- eh/4∏m
(μ) (2B)/h = V
3. The attempt at a solution
First find μz:
μz = (+/- 1.60 x 10-19 C) (6.63 x 10-34 Js/ (4∏) (9.11 x 10-31 kg)
μz = 9.30 x 10-24 Am2
Find V:
μ = hV/2 B
V = (μ) (2B)/h = (9.30 x 10-24 Am2) (2 * 10 T)/(6.63 x 10-34 J s)
V = 2.81 x 106 V
B) (2.81 x 106 V)/(13.6 V) = 2.07 x 105
Is this correct?
The z component of the magnetic dipole moment due to the spin of an electron about its axis is μz = +/- eh/4∏m, where h = 6.63 x 10-34 J s is Planck's constant. A) If μz is parallel to a magnetic field of 10 T, how much energy in electron volts must be supplied to reverse its direction so that it is opposite to the field?
B) Find the ratio of this energy to the 13.6 eV needed to remove an electron from a normal hydrogen atom.
2. Relevant equations
μz = +/- eh/4∏m
(μ) (2B)/h = V
3. The attempt at a solution
First find μz:
μz = (+/- 1.60 x 10-19 C) (6.63 x 10-34 Js/ (4∏) (9.11 x 10-31 kg)
μz = 9.30 x 10-24 Am2
Find V:
μ = hV/2 B
V = (μ) (2B)/h = (9.30 x 10-24 Am2) (2 * 10 T)/(6.63 x 10-34 J s)
V = 2.81 x 106 V
B) (2.81 x 106 V)/(13.6 V) = 2.07 x 105
Is this correct?
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