Tension headache!

jeudi 29 août 2013

1. The problem statement, all variables and given/known data

a mass of 0.5kg is suspended from a flywheel. if the mass is released from rest and falls a distance of 0.5m in 1.5s, calculate : The tension in the rope. acceleration is 0.444ms-2.





2. Relevant equations

t-w = -ma





3. The attempt at a solution



t = m(ag)



t = 0.5(0.4444=9.81)



t = 5.127n



w = mg = 0.5x9.81 4.9n



so t-w 0.227n is rope tension.



Check by inserting numbers into equation of t-w = -ma



so: 5.127 - 4.905 = 0.5 x 0.222.



The last equation doesn`t marry up?






via Physics Forums RSS Feed http://www.physicsforums.com/showthread.php?t=707714&goto=newpost

0 commentaires:

Enregistrer un commentaire