1. The problem statement, all variables and given/known data
2. Relevant equations
3. The attempt at a solution
Question 1
1.1) 5 m.s
1.2) Acceleration
1.3) 10 m.s^-2
1.4) Displacement equals area under graph = 1/2*b*h = 1/2*2*10 = 10 m
1.5) vf = vi+at
0 = 10 + 10t
t = 1's + 2's = 3's
1.6) 1/2*1*10 = 5m
Position of ball = 10-5 = 5m
Question 2
2.1) Total mechanical energy in an isolated system is conserved
2.2) Total Mech Eergy at A = Total Mechanical Energy At B
Mech at A = mgh
= 1.5*9.8*0.6
= 8.82 J
Emech = mgh+Ek
8.82 = 1.5*9.8*0.2 +ek
ek = 5.88 J
2.3) Velocity a B:
Ek = 0.5mv^2
5.88 = 0.5*1.5*v^2
v = 2.8 m.s
Wnet = Work done by water
Wnet = change in ek
= 1/2m(vf^2-vi^2)
= 0.5*1.5(0-2.8^2)
= 5.88 J
2. Relevant equations
3. The attempt at a solution
Question 1
1.1) 5 m.s
1.2) Acceleration
1.3) 10 m.s^-2
1.4) Displacement equals area under graph = 1/2*b*h = 1/2*2*10 = 10 m
1.5) vf = vi+at
0 = 10 + 10t
t = 1's + 2's = 3's
1.6) 1/2*1*10 = 5m
Position of ball = 10-5 = 5m
Question 2
2.1) Total mechanical energy in an isolated system is conserved
2.2) Total Mech Eergy at A = Total Mechanical Energy At B
Mech at A = mgh
= 1.5*9.8*0.6
= 8.82 J
Emech = mgh+Ek
8.82 = 1.5*9.8*0.2 +ek
ek = 5.88 J
2.3) Velocity a B:
Ek = 0.5mv^2
5.88 = 0.5*1.5*v^2
v = 2.8 m.s
Wnet = Work done by water
Wnet = change in ek
= 1/2m(vf^2-vi^2)
= 0.5*1.5(0-2.8^2)
= 5.88 J
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