1. The problem statement, all variables and given/known data
A train is traveling down a straight track at 20 m/s when the engineer applies the brakes, resulting in an acceleration of -1.0 m/s2 as long as the train is in motion. How far does the train move in a 40-s time interval starting at the instant the brakes are applied?
2. Relevant equations
[itex]\Delta[/itex]x = v0t + (1/2)at2
3. The attempt at a solution
Answer from the back of the book: 200 m, but my answer does not agree!
[itex]\Delta[/itex]x = v0t + (1/2)at2
[itex]\Delta[/itex]x = (20 m/s)(40 s) + (1/2)(-1.0 m/s2)(40 s)2
[itex]\Delta[/itex]x = 800 m + (1/2)(-1,600 m)
[itex]\Delta[/itex]x = 800 m - 800 m
[itex]\Delta[/itex]x = 0 m
This has to be wrong! I have gone over the calculations and the equation numerous times, and I can't find anything wrong though. Can anyone help?
Thanks!
A train is traveling down a straight track at 20 m/s when the engineer applies the brakes, resulting in an acceleration of -1.0 m/s2 as long as the train is in motion. How far does the train move in a 40-s time interval starting at the instant the brakes are applied?
2. Relevant equations
[itex]\Delta[/itex]x = v0t + (1/2)at2
3. The attempt at a solution
Answer from the back of the book: 200 m, but my answer does not agree!
[itex]\Delta[/itex]x = v0t + (1/2)at2
[itex]\Delta[/itex]x = (20 m/s)(40 s) + (1/2)(-1.0 m/s2)(40 s)2
[itex]\Delta[/itex]x = 800 m + (1/2)(-1,600 m)
[itex]\Delta[/itex]x = 800 m - 800 m
[itex]\Delta[/itex]x = 0 m
This has to be wrong! I have gone over the calculations and the equation numerous times, and I can't find anything wrong though. Can anyone help?
Thanks!
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