1. The problem statement, all variables and given/known data
Find the formula of the partial sum of the series Ʃ1/[k(k+2)] k from 1 to infinity
2. Relevant equations
3. The attempt at a solution
Using partial fractions i rewrite the series as 1/2*Ʃ[1/k] - [1/(k+2)]
Then I start writing out the series from k=1 to 5.
1/2*[(1-1/3)+(1/2-1/4)+(1/3-1/5)+(1/4-1/6)+(1/5-1/7)+...+(1/n-1/(n+2))]
Everything cancels except for 1-1/6-1/7+(1/n-1/(n+2))
I think that Sn=1/2*(1+1/2-1/(n+2)-1/(n+2))
My professor in class solved it as 1/2*(1+1/2-1/(n+1)-1/(n+2))
I don't understand where the 1/n+1 term comes from. Is he right or am I, and why?
1. The problem statement, all variables and given/known data
2. Relevant equations
3. The attempt at a solution
Find the formula of the partial sum of the series Ʃ1/[k(k+2)] k from 1 to infinity
2. Relevant equations
3. The attempt at a solution
Using partial fractions i rewrite the series as 1/2*Ʃ[1/k] - [1/(k+2)]
Then I start writing out the series from k=1 to 5.
1/2*[(1-1/3)+(1/2-1/4)+(1/3-1/5)+(1/4-1/6)+(1/5-1/7)+...+(1/n-1/(n+2))]
Everything cancels except for 1-1/6-1/7+(1/n-1/(n+2))
I think that Sn=1/2*(1+1/2-1/(n+2)-1/(n+2))
My professor in class solved it as 1/2*(1+1/2-1/(n+1)-1/(n+2))
I don't understand where the 1/n+1 term comes from. Is he right or am I, and why?
1. The problem statement, all variables and given/known data
2. Relevant equations
3. The attempt at a solution
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