1. The problem statement, all variables and given/known data
A mass of 0.5kg is suspended from a flywheel. If the mass is released from rest and falls a distance of 0.5m in 1.5s. ( mass of wheel = 3kg, Radius = 0.3m, Radius of gyration = 212mm ).
Calculate : a:The linear acceleration of the mass?
b: The angular acceleration of the wheel?
2. Relevant equations
v=s/t
a= v-u/t
s=ut+1/2at^2
3. The attempt at a solution
I am getting conflicting answers to these questions. Heres my attempt!
v = s/t so... v = 0.5/1.5 = 0.3333ms-1.
Then...
a = v-u/t so... v = 0.3333 - 0/1.5 = 0.2222ms-2
So linear acceleration = 0.2222ms-2
Question b : angular acceleration = acceleration/radius.
so...
angular acceleration = 0.2222/ 0.3 = 0.74 Rads-2.
Now my linear acceleration is 0.222ms-2
so if i put this answer into the equation s = ut + 1/2at^2. s should equal 0.5m. so..
s = 1.5+1/2X0.2222x1.5^2 = 1.75s??? The answer should be 0.5m?
Any help will be greatfully accepted.
A mass of 0.5kg is suspended from a flywheel. If the mass is released from rest and falls a distance of 0.5m in 1.5s. ( mass of wheel = 3kg, Radius = 0.3m, Radius of gyration = 212mm ).
Calculate : a:The linear acceleration of the mass?
b: The angular acceleration of the wheel?
2. Relevant equations
v=s/t
a= v-u/t
s=ut+1/2at^2
3. The attempt at a solution
I am getting conflicting answers to these questions. Heres my attempt!
v = s/t so... v = 0.5/1.5 = 0.3333ms-1.
Then...
a = v-u/t so... v = 0.3333 - 0/1.5 = 0.2222ms-2
So linear acceleration = 0.2222ms-2
Question b : angular acceleration = acceleration/radius.
so...
angular acceleration = 0.2222/ 0.3 = 0.74 Rads-2.
Now my linear acceleration is 0.222ms-2
so if i put this answer into the equation s = ut + 1/2at^2. s should equal 0.5m. so..
s = 1.5+1/2X0.2222x1.5^2 = 1.75s??? The answer should be 0.5m?
Any help will be greatfully accepted.
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