Thevenin Equivalent Circuit

mardi 1 octobre 2013

1. The problem statement, all variables and given/known data





Above given is the circuit I am supposed to simplify where the 1/5Ω resistor is the load. I'm unsure how to convert this circuit into an equivalent Thevenin Circuit.



2. Relevant equations



V = I*R (Ohm's Law)



3. The attempt at a solution



Using Microcap and it's Dynamic DC Analysis Tool, I measured the current flow at the load. I managed to break it down to this:







Where V5 was a 2/3V voltage source. (2A current source in series with the 1/3Ω resistor).



If this is correct, I would then say that the 2/3V voltage source and the 4A current source were in series and that the V4 voltage source and the 1/6Ω resistor were in series. Is this the correct approach?






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