This problem has been bugging me for a while...
If a stone thrown from a bridge strikes the water 10.0 m below after 1.70 s, what was the stone's initial velocity?
My first attempt was to use Δy = vyi(Δt) +0.5(g) (Δt)^2 because I understand that the time to fall is dependent only on gravity.
I keep getting an initial velocity of -14.22 m/s. The given answer is 2.45 m/s upward. What gives?
I get the feeling that I'm missing something simple.
If a stone thrown from a bridge strikes the water 10.0 m below after 1.70 s, what was the stone's initial velocity?
My first attempt was to use Δy = vyi(Δt) +0.5(g) (Δt)^2 because I understand that the time to fall is dependent only on gravity.
I keep getting an initial velocity of -14.22 m/s. The given answer is 2.45 m/s upward. What gives?
I get the feeling that I'm missing something simple.
via Physics Forums RSS Feed http://www.physicsforums.com/showthread.php?t=719608&goto=newpost
0 commentaires:
Enregistrer un commentaire