Calculating current through an IR circuit

mardi 1 octobre 2013

Hi, if I have a DC indoctor-resistor circuit with and inductance (L) of 700μH and a resistance (R) of 0.8Ω, I realise that I can use:



IL = (Vsource/R) * (1-e-t*(R/L))



to calculate the current through the inductor if I have a constant voltage source, but would it be possible to calculate how the current build (and also decay) might look in this or a similar method if my source voltage looked more like:







So far I can't work out how to make this work with a changing voltage, as the equation appears to assume that you always start at 0



Also, on the decay side, the equation:



IL = (Vsource/R) * (e-t*(R/L))



Seems to assume that you always start at current I=V/R, which is not always necessarily true



I hope I've explained myself well enough, and thanks for any help in advance!






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