In the vertical jump, an athlete starts from a crouch and jumps upward to reach as high as possible. Even the best athletes spend little more than 1.00 s in the air (their "hang time"). Treat the athlete as a particle and let ymax be his maximum height above the floor.
To explain why he seems to hang in the air, calculate the ratio of the time he is above ymax/2 moving up to the time it takes him to go from the floor to that height. You may ignore air resistance.
v = u + at
s = ut + 1/2at^2
The wording of this question is really confusing me. So I need to calculate the ratio of the time he is above ymax/2 (t1) : the time it takes him to go from the floor to ymax/2 (t2)? So its just the ratio t1:t2?
To explain why he seems to hang in the air, calculate the ratio of the time he is above ymax/2 moving up to the time it takes him to go from the floor to that height. You may ignore air resistance.
v = u + at
s = ut + 1/2at^2
The wording of this question is really confusing me. So I need to calculate the ratio of the time he is above ymax/2 (t1) : the time it takes him to go from the floor to ymax/2 (t2)? So its just the ratio t1:t2?
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