1. The problem statement, all variables and given/known data
a parallel plate capacitor has 2 plates separated by a dielectric of rel. permittivity 5.0 are separated by 0.20mm and have area of 5.0 cm2.
Potential difference between the plates is 500V.
I need to be able to calculate the free surface charge density.
2. Relevant equations
I'm assuming Dout = Din
From boundary conditions D1 ┴ = D2 ┴
and D2 ┴ - D1 ┴ = σf
Could someone just confirm what the boundary conditions are so I can say that the free surface charge density is zero or not!
3. The attempt at a solution
I have Dout = Din = ε0Ein + P
so from calculations
P = 4.43x10-9 - (8.85x10-12 x 100)
P = 3.54x10-9 Cm-2
Could I just say;
D1 ┴ = D2 ┴ so there is zero free surface charge density!
a parallel plate capacitor has 2 plates separated by a dielectric of rel. permittivity 5.0 are separated by 0.20mm and have area of 5.0 cm2.
Potential difference between the plates is 500V.
I need to be able to calculate the free surface charge density.
2. Relevant equations
I'm assuming Dout = Din
From boundary conditions D1 ┴ = D2 ┴
and D2 ┴ - D1 ┴ = σf
Could someone just confirm what the boundary conditions are so I can say that the free surface charge density is zero or not!
3. The attempt at a solution
I have Dout = Din = ε0Ein + P
so from calculations
P = 4.43x10-9 - (8.85x10-12 x 100)
P = 3.54x10-9 Cm-2
Could I just say;
D1 ┴ = D2 ┴ so there is zero free surface charge density!
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