1. The problem statement, all variables and given/known data
Consider the plane 3x1-x2+2x3 = 0 in R3. Find a basis for this plane. Hint: It's not hard to find vectors in this plane.
2. Relevant equations
Plane: 3x1-x2+2x3 = 0 in R3.
3. The attempt at a solution
Let,
A = [itex]\left[3,\right.\left.-1,\right.\left.2\right][/itex] [itex]\rightarrow[/itex] [itex]\left[\frac{3}{3},\right.\left.\frac{-1}{3},\right.\left.\frac{2}{3}\right][/itex] (Row Reduced)
[itex]\Rightarrow[/itex] x1 = [itex]\frac{1}{3}[/itex]x2-[itex]\frac{2}{3}[/itex]x3, x2 is free, x3 is free.
[itex]\Rightarrow[/itex] [itex]\left\{x_2[\frac{1}{3},1,0]+x_3[\frac{-2}{3},0,1] | x_2, x_3 \in R\right\}[/itex]
[itex]\Rightarrow[/itex] Basis of Plane = [itex]\left\{[\frac{1}{3},1,0],[\frac{-2}{3},0,1]\right\}[/itex]
Consider the plane 3x1-x2+2x3 = 0 in R3. Find a basis for this plane. Hint: It's not hard to find vectors in this plane.
2. Relevant equations
Plane: 3x1-x2+2x3 = 0 in R3.
3. The attempt at a solution
Let,
A = [itex]\left[3,\right.\left.-1,\right.\left.2\right][/itex] [itex]\rightarrow[/itex] [itex]\left[\frac{3}{3},\right.\left.\frac{-1}{3},\right.\left.\frac{2}{3}\right][/itex] (Row Reduced)
[itex]\Rightarrow[/itex] x1 = [itex]\frac{1}{3}[/itex]x2-[itex]\frac{2}{3}[/itex]x3, x2 is free, x3 is free.
[itex]\Rightarrow[/itex] [itex]\left\{x_2[\frac{1}{3},1,0]+x_3[\frac{-2}{3},0,1] | x_2, x_3 \in R\right\}[/itex]
[itex]\Rightarrow[/itex] Basis of Plane = [itex]\left\{[\frac{1}{3},1,0],[\frac{-2}{3},0,1]\right\}[/itex]
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