Finding the value for k that gives the system
a) a unique solution?
b) no solution
c) an infinite number of solutions?
x − 2z = − 3
x + y + (k + 2) z = 1
2x − ky − z = − 2
So the matrix is
1 0 -2 -3
1 1 (k+2) 1
2 -k -1 -2
It also says "HINT: You should find this factorisation useful: k2 + 4k + 3 = (k + 3)(k + 1)"
I don't see how that information is useful. Shouldn't I just find the values of k that make a)/b)/c) true?
a) a unique solution?
b) no solution
c) an infinite number of solutions?
x − 2z = − 3
x + y + (k + 2) z = 1
2x − ky − z = − 2
So the matrix is
1 0 -2 -3
1 1 (k+2) 1
2 -k -1 -2
It also says "HINT: You should find this factorisation useful: k2 + 4k + 3 = (k + 3)(k + 1)"
I don't see how that information is useful. Shouldn't I just find the values of k that make a)/b)/c) true?
0 commentaires:
Enregistrer un commentaire