1. The problem statement, all variables and given/known data
a stone is thrown vertically downward from the top of 40 m tall building with an initial speed of 1 after 2s the stone will have traveled a distance of?
2. Relevant equations
x=vt+0.5at^2
vf=vi+at
3. The attempt at a solution
1(2)+0.5(-9.8)(2)^2=-17.6
the answer i was given is 22
and i tried to put 9.8 without negative and it was 21.6 is this one right ??
why is the acceleration positive while going up is negative ???
waiting and thank you
a stone is thrown vertically downward from the top of 40 m tall building with an initial speed of 1 after 2s the stone will have traveled a distance of?
2. Relevant equations
x=vt+0.5at^2
vf=vi+at
3. The attempt at a solution
1(2)+0.5(-9.8)(2)^2=-17.6
the answer i was given is 22
and i tried to put 9.8 without negative and it was 21.6 is this one right ??
why is the acceleration positive while going up is negative ???
waiting and thank you
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