I know that[tex] \oint \vec E \cdot \vec{dS} [/tex] in Gauss Law indicates electric flux .
[tex] \oint \vec E \cdot \vec{dS} = \frac{Q_{enc}}{\varepsilon_0} [/tex]
But what does B.dl indicate in Ampere's Law?
##\oint \vec{B} \cdot \vec{dl} ## = ??
What does B.dl indicate in Ampere's Law
[tex] \oint \vec E \cdot \vec{dS} = \frac{Q_{enc}}{\varepsilon_0} [/tex]
But what does B.dl indicate in Ampere's Law?
##\oint \vec{B} \cdot \vec{dl} ## = ??
What does B.dl indicate in Ampere's Law
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