A block of mass m is at rest at the origin at t=0. It is pushed with constant force F0 from x=0 to x=L across a horizontal surface whose coefficient of kinetic friction is μk=μ0(1−x/L). That is, the coefficient of friction decreases from μ0 at x=0 to zero at x=L.
find an expression for the block's velocity when it reaches position x=L.
Express your answer in terms of the variables L, F0, m, μ0, and appropriate constants.
(F0 - mg(1-x/L))/m = a
I took the integral to find the velocity and I got
v = √(2(F0mL+μ0g))
and it was wrong.... Can someone please help
find an expression for the block's velocity when it reaches position x=L.
Express your answer in terms of the variables L, F0, m, μ0, and appropriate constants.
(F0 - mg(1-x/L))/m = a
I took the integral to find the velocity and I got
v = √(2(F0mL+μ0g))
and it was wrong.... Can someone please help
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